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5.4x^2+9.7x-8.6=0
a = 5.4; b = 9.7; c = -8.6;
Δ = b2-4ac
Δ = 9.72-4·5.4·(-8.6)
Δ = 279.85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.7)-\sqrt{279.85}}{2*5.4}=\frac{-9.7-\sqrt{279.85}}{10.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.7)+\sqrt{279.85}}{2*5.4}=\frac{-9.7+\sqrt{279.85}}{10.8} $
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